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# How is gear reduction achieved?

Categories: Latest NewsRelease time: 2016-03-07 10:07:00
Source: ZHAOWEIEditor: ZHAOWEI Author: ZHAOWEI

Many small reducer types are capable of attaining gear reduction including, but not limited to, parallel shaft, planetary and right-angle worm gearboxes.  In parallel shaft gearboxes (or reducers), a pinion gear with a certain number of teeth meshes and drives a larger gear with a greater number of teeth.  The “reduction” or gear ratio is calculated by dividing the number of teeth on the large gear by the number of teeth on the small gear.  For example, if an electric motor drives a 13-tooth pinion gear that meshes with a 65-tooth gear, a reduction of 5:1 is achieved (65 / 13 = 5).  If the electric motor speed is 3,450 rpm, the gearbox reduces this speed by five times to 690 rpm.  If the motor torque is 10 lb-in, the gearbox increases this torque by a factor of five to 50 lb-in (before subtracting out gearbox efficiency losses).

Parallel shaft gearboxes many times contain multiple gear sets thereby increasing the gear reduction.  The total gear reduction (ratio) is determined by multiplying each individual gear ratio from each gear set stage.  If a gearbox contains 3:1, 4:1 and 5:1 gear sets, the total ratio is 60:1 (3 x 4 x 5 = 60).  In our example above, the 3,450 rpm electric motor would have its speed reduced to 57.5 rpm by using a 60:1 gearbox.  The 10 lb-in electric motor torque would be increased to 600 lb-in (before efficiency losses).

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